Suppose $\vect{u},\,\vect{v}\in\complex{m}$ and $\alpha\in\complex{\null}$. Then

1. $\innerproduct{\alpha\vect{u}}{\vect{v}}=\conjugate{\alpha}\innerproduct{\vect{u}}{\vect{v}}$
2. $\innerproduct{\vect{u}}{\alpha\vect{v}}=\alpha\innerproduct{\vect{u}}{\vect{v}}$