Solution TSS.C27 Chris Black
The augmented matrix for the given linear system and its row-reduced form are: \begin{align*} \begin{bmatrix} 1 & 2 & 3 & 0\\ 2 & -1 & 1 & 2\\ 1 & -8 & -7 & 1\\ 0 & 1 & 1 & 0 \end{bmatrix} \rref \begin{bmatrix} \leading{1} & 0 & 1 & 0\\ 0 & \leading{1} & 1 & 0\\ 0 & 0 & 0 & \leading{1}\\ 0 & 0 & 0 & 0 \end{bmatrix}. \end{align*} For this system, we have $n = 3$ and $r = 3$. However, with a pivot column in the last column we see that the original system has no solution by Theorem RCLS.