Solution TSS.C26 Chris Black
The augmented matrix for the given linear system and its row-reduced form are: \begin{align*} \begin{bmatrix} 1 & 2 & 3 & 1\\ 2 & -1 & 1 & 2\\ 3 & 1 & 1 & 4\\ 0 & 5 & 2 & 1 \end{bmatrix} \rref \begin{bmatrix} \leading{1} & 0 & 0 & 4/3\\ 0 & \leading{1} & 0 & 1/3\\ 0 & 0 & \leading{1} & -1/3\\ 0 & 0 & 0 & 0 \end{bmatrix}. \end{align*} Since $r = n = 3$ and the system is consistent by Theorem RCLS, Theorem CSRN guarantees a unique solution, which is \begin{align*} x_1 &= 4/3\\ x_2 &= 1/3\\ x_3 &= -1/3. \end{align*}