Solution SD.T15 Robert Beezer
By Definition SIM we know that there is a nonsingular matrix $S$ so that $A=\similar{B}{S}$. Then \begin{align*} A^3&=(\similar{B}{S})^3\\ &=(\similar{B}{S})(\similar{B}{S})(\similar{B}{S})\\ &=\inverse{S}B(S\inverse{S})B(S\inverse{S})BS&&\knowl{./knowls/theorem.MMA.knowl}{\text{Theorem MMA}}\\ &=\inverse{S}B(I_n)B(I_n)BS&&\knowl{./knowls/definition.MI.knowl}{\text{Definition MI}}\\ &=\inverse{S}BBBS&&\knowl{./knowls/theorem.MMIM.knowl}{\text{Theorem MMIM}}\\ &=\inverse{S}B^3S \end{align*} This equation says that $A^3$ is similar to $B^3$ (via the matrix $S$).

More generally, if $A$ is similar to $B$, and $m$ is a non-negative integer, then $A^m$ is similar to $B^m$. This can be proved using induction (Proof Technique I).