Solution ILT.C27 Chris Black
If $\lt{T}{\colvector{x\\y\\z}} = \zerovector$, then $\colvector{2x + y + z\\x - y + 2z\\x + 2y - z} = \zerovector$. Thus, we have the system \begin{align*} 2x + y + z &= 0\\ x - y + 2z &= 0\\ x + 2y - z &= 0 \end{align*} . Thus, we are looking for the nullspace of the matrix $A_T = \begin{bmatrix} 2& 1 & 1\\ 1 & -1 & 2\\ 1 & 2 & -1 \end{bmatrix}$. Since $A_T$ row-reduces to $\begin{bmatrix} \leading{1} & 0 & 1\\ 0 & \leading{1} & -1 \\ 0 & 0 & 0 \end{bmatrix}$, the kernel of $T$ is all vectors where $x = -z$ and $y = z$. Thus, $\krn{T} = \spn{\set{\colvector{ -1\\1\\1}}}$.

Since the kernel is not trivial, Theorem KILT tells us that $T$ is not injective.