Proof of Theorem SCB

In the conclusion of Theorem MRCB, replace $D$ by $B$, and replace $E$ by $C$, \begin{align*} \matrixrep{T}{B}{B} &=\cbm{C}{B}\matrixrep{T}{C}{C}\cbm{B}{C}&&\knowl{./knowls/theorem.MRCB.knowl}{\text{Theorem MRCB}}\\ &=\inverse{\cbm{B}{C}}\matrixrep{T}{C}{C}\cbm{B}{C}&&\knowl{./knowls/theorem.ICBM.knowl}{\text{Theorem ICBM}} \end{align*}