The matrix \begin{equation*} E=\begin{bmatrix} 0 & 4 & -1 & 2 & 2 & 3 & 1\\ 2 & -2 & 1 & -1 & 0 & -4 & -3\\ -2 & -3 & 9 & -3 & 9 & -1 & 9\\ -3 & -4 & 9 & 4 & -1 & 6 & -2\\ -3 & -4 & 6 & -2 & 5 & 9 & -4\\ 9 & -3 & 8 & -2 & -4 & 2 & 4\\ 8 & 2 & 2 & 9 & 3 & 0 & 9 \end{bmatrix} \end{equation*} is row-equivalent to the matrix in reduced row-echelon form, \begin{equation*} \begin{bmatrix} \leading{1} & 0 & 0 & 0 & 0 & 0 & 0\\ 0 & \leading{1} & 0 & 0 & 0 & 0 & 0\\ 0 & 0 & \leading{1} & 0 & 0 & 0 & 0\\ 0 & 0 & 0 & \leading{1} & 0 & 0 & 0\\ 0 & 0 & 0 & 0 & \leading{1} & 0 & 0\\ 0 & 0 & 0 & 0 & 0 & \leading{1} & 0\\ 0 & 0 & 0 & 0 & 0 & 0 & \leading{1} \end{bmatrix} \end{equation*}
With $n=7$ columns and $r=7$ nonzero rows Theorem CRN tells us the rank is $\rank{E}=7$ and the nullity is $\nullity{E}=7-7=0$.