The norm of \begin{equation*} \vect{u}=\colvector{3+2i\\1-6i\\2+4i\\2+i} \end{equation*} is \begin{align*} \norm{\vect{u}}&= \sqrt{\modulus{3+2i}^2+\modulus{1-6i}^2+\modulus{2+4i}^2+\modulus{2+i}^2}\\ &=\sqrt{13+37+20+5}=\sqrt{75}=5\sqrt{3} \end{align*}
The norm of \begin{equation*} \vect{v}=\colvector{3\\-1\\2\\4\\-3} \end{equation*} is \begin{equation*} \norm{\vect{v}}= \sqrt{\modulus{3}^2+\modulus{-1}^2+\modulus{2}^2+\modulus{4}^2+\modulus{-3}^2} =\sqrt{3^2+1^2+2^2+4^2+3^2}=\sqrt{39}. \end{equation*}